From: pete@versatilecoding.com   
      
   On 2012-05-12 10:10:03 +0000, Seungbeom Kim said:   
      
   > On 2012-05-11 18:30, Pete Becker wrote:   
   >> On 2012-05-11 19:21:54 +0000, Marc said:   
   >>   
   >>> I have several overloads of a function, I have a set of arguments, and   
   >>> I would like to get a function pointer to the overload the compiler   
   >>> would pick if I called this function on these arguments. I am not   
   >>> interested in applying the function now, I just want to get that   
   >>> pointer.   
   >>>   
   >>> Is this possible? Or is anything vaguely similar possible?   
   >>   
   >> Use a cast to select from a set of overloaded functions:   
   >>   
   >> void f(int);   
   >> void f(double);   
   >>   
   >> typedef void (*f_of_double)(double);   
   >>   
   >> f_of_double fptr = (f_of_double)&f;   
   >>   
   >> The typedef isn't actually needed; I used it here to clarify what's   
   >> going on. Yes, the cast looks wierd, but that's the rule.   
   >   
   > You don't actually need the cast either, do you?   
   >   
   > void (*f_int)(int)       = &f;  // points to f(int)   
   > void (*f_double)(double) = &f;  // points to f(double)   
      
   Good point. No, you don't need it if the left-hand side determines the   
   type. You do need it when it doesn't:   
      
   template  void call_it(T);   
      
   call_it(&f);	// ambiguous   
   call_it((f_of_double)&f);	// OK   
      
   --   
    Pete   
   Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The   
   Standard C++ Library Extensions: a Tutorial and Reference   
   (www.petebecker.com/tr1book)   
      
      
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