39ede19f   
   From: francis.glassborow@btinternet.com   
      
   On 17/05/2012 14:44, PiotrN wrote:   
   > On 17 Maj, 09:13, ravinder thakur  wrote:   
   >> int x = 10;   
   >> x = x++;   
   >>   
   >> I expect value of x to be 10 after the second assignment, however   
   >> its coming out to be 11. Any ideas whats happening ?   
   >>   
   >   
   > I believe this is equivalent to:   
   >   
   > int x = 10;   
   > x = x, ++x;   
   >   
   > So it is obvious, x is 11 after all.   
   >   
   > Consider this:   
   > int x = 10;   
   > int a;   
   > a = x++;   
   >   
   > a is 10 and x is 11   
   > same as for this code:   
   > a = x, ++x;   
   >   
   > HTH,   
   > Piotr   
   >   
   >   
      
   Please note that the explanations people are giving for the result are   
   spurious because the Standard makes no requirements for the   
   consequences of writing twice to the same storage without an   
   intervening sequence point. It is true that almost always executing   
   that statement will result in either x being 10 or x being 11 but it   
   could result in anything including shutting down your computer.   
      
   Francis   
      
      
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