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|    comp.lang.c++.moderated    |    Moderated discussion of C++ superhackery    |    33,346 messages    |
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|    Message 32,512 of 33,346    |
|    Kaba to All    |
|    Re: Return-type deduction for all functi    |
|    10 Aug 12 14:35:46    |
      From: kaba@nowhere.com              10.8.2012 21:19, Francis Glassborow kirjoitti:       > On 09/08/2012 19:51, Kaba wrote:       >> Would it make sense to generalize the implicit return-type       >> deduction of the lambda functions to all functions? Motivation:       >> reading the Boost.Proto documentation and seeing something like       >> this:       >>       > But the problem is that only a function declaration is needed in       > order to call a function. How will the caller know what the return       > type is?              Perhaps the exact type is not always important to the user, such as in       this Proto-example. What is important though is the underlying concept       the type implements. However, without support from the language the       concept would have to be looked up from the documentation; I could       live with that:) But something like this would be even nicer:               auto[Grammar_Concept] f();              --       http://kaba.hilvi.org                      [ See http://www.gotw.ca/resources/clcm.htm for info about ]        [ comp.lang.c++.moderated. First time posters: Do this! ]              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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