From: daniel.kruegler@googlemail.com   
      
   Am 25.09.2012 22:14, schrieb kiran:   
   > Here is a code snippet:   
   > =============   
   > int **ptr;   
   > int intArr[3][5];   
   > ptr = intArr;   
   > =============   
   >   
   > This gives the error on g++ compiler:   
   > error: cannot convert ‘int [3][5]’ to ‘int**’ in assignment   
   >   
   > I have tried other variants as well, like   
   > int const **ptr = intArr;   
   > and   
   > ptr = &intArr[0];   
   >   
   > I still got the same error. Can anyone explain the reason here.   
      
   The reason for this is, because array-to-pointer conversion does not   
   have an arbitrary depth. The relevant wording in 4.2 [conv.array] p1 is:   
      
   "An lvalue or rvalue of type “array of N T” or “array of unknown bound   
   of T” can be converted to a prvalue of type “pointer to T”. The result   
   is a pointer to the first element of the array."   
      
   Applied to your example we have intArr, which has type "array of 3 array   
   of 5 int". The quoted wording says that this type can undergo an   
   array-to-pointer conversion to type "pointer to array of 5 int", which   
   can be written as the type int (*)[5]. Note that at this point we have   
   no longer an array anymore, therefore no further decay to int** is possible.   
      
   HTH & Greetings from Bremen,   
      
   Daniel Krügler   
      
      
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