From: francis.glassborow@btinternet.com   
      
   On 03/10/2012 00:23, Simon Parmenter wrote:   
   > Hi All   
   >   
   > I was just playing around with some test code I had done sometime ago and   
   > found some behaviour I could not explain; looking up the C++11 standard   
   > did me no good either.   
   >   
   > It may be the std::string implementation - just guessing here.   
   > So what do you think?   
   >   
      
   I think your problem concerns not recognising a library defined operator.   
      
   when you wrote:   
      
   s1 + s2 = "Eh?";   
      
   the compiler sees:   
      
   operator=(s1+s2, "Eh?");   
      
   It evaluates s1+s2 as a temporary of type std::string and passes that   
   along with the second argument to the relevant operator=(). Where the   
   new features of C++11 cut in is in allowing (in this context) a   
   temporary to be bound to a non-const reference parameter   
      
      
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