From: daniel.kruegler@googlemail.com   
      
   Am 09.10.2012 20:19, schrieb Helmut Jarausch:   
   > Hi,   
   >   
   > I have seen the following code in template functions   
   >   
   > { using std::sqrt;  return sqrt(...)); }   
      
   I assume that ... stands for some valid C++ expression.   
      
   > Is this equivalent to   
   >   
   > { return std::sqrt(....); }   
      
   No.   
      
   > or are there any "side effects" on overload resolution, ADL or similar?.   
      
   If you write a qualified function call like std::sqrt, then no ADL will   
   take place, only functions from namespace std will be considered.   
      
   But if you write your second form you have "ADL-enabled" your code. It   
   will consider all overloads of sqrt from namespace std but it will -   
   depending on the function call arguments consider sqrt overloads in   
   associated namespaces of the argument type. This is often intended, e.g.   
   when using swap.   
      
   HTH & Greetings from Bremen,   
      
   Daniel Krügler   
      
      
      
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