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|    comp.lang.c++.moderated    |    Moderated discussion of C++ superhackery    |    33,346 messages    |
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|    Message 32,597 of 33,346    |
|    red floyd to All    |
|    Re: Strange convertion    |
|    19 Oct 12 15:36:03    |
   
   From: no.spam.here@its.invalid   
      
   On 10/19/2012 1:04 PM, Vianney Lançon wrote:   
   > Hello,   
   >   
   > while compiling our code we found that a wrong constructor was called.   
   >   
   > The code was something like that.   
   >   
   >   
   > #include    
   > struct Toto   
   > {   
   > Toto(unsigned short a[2]){ x=a[0]; y=a[1];}   
   > unsigned short x, y;   
   > };   
   > void print(const Toto& toto)   
   > {   
   > std::cout< }   
   > int main()   
   > {   
   > print(false); // <= convert false to Toto   
   > return 0;   
   > }   
   >   
   >   
   > Because the constructor of Toto is not explicit it is normal that   
   > unsigned short[4] can be converterd to Toto.   
   >   
   > But I do not understand by what mechanisme the bool value false can be   
   > convert into unsigned short[4].   
   >   
   > Because it doesn't compile if i change the value from false to true it   
   > 's probably because of some convertion from false to 0 literal.   
      
   I believe it's because unsigned short[2] decays to unsigned short*.   
   The chain then is false => 0 => (unsigned short*)0.   
      
      
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