From: no.spam.here@its.invalid   
      
   On 10/19/2012 3:36 PM, red floyd wrote:   
   > On 10/19/2012 1:04 PM, Vianney Lançon wrote:   
   >> Hello,   
   >>   
   >> while compiling our code we found that a wrong constructor was called.   
   >>   
   >> The code was something like that.   
   >>   
   >>   
   >> #include    
   >> struct Toto   
   >> {   
   >> Toto(unsigned short a[2]){ x=a[0]; y=a[1];}   
   >> unsigned short x, y;   
   >> };   
   >> void print(const Toto& toto)   
   >> {   
   >> std::cout<> }   
   >> int main()   
   >> {   
   >> print(false);  // <= convert false to Toto   
   >> return 0;   
   >> }   
   >>   
   >>   
   >> Because the constructor of Toto is not explicit it is normal that   
   >> unsigned short[4] can be converterd to Toto.   
   >>   
   >> But I do not understand by what mechanisme the bool value false can be   
   >> convert into unsigned short[4].   
   >>   
   >> Because it doesn't compile if i change the value from false to true it   
   >> 's probably because of some convertion from false to 0 literal.   
   >   
   > I believe it's because unsigned short[2] decays to unsigned short*.   
   > The chain then is false => 0 => (unsigned short*)0.   
      
   If you want an array only, pass a reference to it.   
      
   Toto(unsigned short (&a)[2]);   
      
   This will *ONLY* accept an array of 2 shorts.   
      
      
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