From: daniel.kruegler@googlemail.com   
      
   On 2012-11-23 00:24, Daniel Krügler wrote:   
   > The call to std::move just produces an xvalue   
   > of T (assuming that T is not an lvalue-reference).   
      
   Of-course including T being an lvalue-reference. I don't know what I was   
   writing here.   
      
   I apologize for any confusion caused,   
      
   Greetings from Bremen,   
      
   Daniel Krügler   
      
      
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