From: ootiib@hot.ee   
      
   On Monday, 4 February 2013 08:44:44 UTC+2, Luca Risolia  wrote:   
   > On 04/02/2013 00:18, DeMarcus wrote:   
   > > I perceive constexpr as an advanced meta-programming "#define" or   
   > > "macro" that replaces the expression with some compile-time computed value.   
   >   
   > Not in general. constexpr is also a function modifier. Although a   
   > constexpr function can be used in constant expressions, this does not   
   > mean that all uses are constant expressions.   
   >   
   > For example:   
   > constexpr int f(int x) { return x+x; }   
   > int a[f(5)]; // okay   
   > int v = 5;   
   > int a[f(v)]; // not ok, v is not a constant expression   
      
   That example fails to support your point.   
   Macro can be also function-like. ;)   
      
     #define F(X) ((X)+(X))   
     int a[F(5)]; // okay   
     int v = 5;   
     int a[F(v)]; // not ok, v is not a constant expression   
      
      
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