From: cuzdav@googlemail.com   
      
   On Thursday, April 18, 2013 9:50:02 PM UTC-5, Jonathan Thornburg wrote:   
   >   
   > // investigate passing vector to a function expecting vector   
      
   If you don't mind making your implementation itself   
   be a template this is pretty easy to accomplish.   
   Here's the idea.  (I extracted the printing   
   of a single interval to a separate function.)   
      
   void print_interval(interval const * pI)   
   {   
       const interval& I = *pI;   
       cout << "interval " << pI << " = "   
            << "[" << I.min() << ", " << I.max() << "]" << "\n";   
   }   
      
   template    
   void print_vector_of_intervals(const std::vector& vci)   
   {   
       for (typename std::vector::template const_iterator it =   
           vci.begin(); it != vci.end(); ++it)   
       {   
           if (*it)   
               print_interval(*it);   
       }   
   }   
      
      
   and of course, with c++0x you can use auto to clean that up.   
      
       for (auto it = vci.cbegin(); it != vci.cend(); ++it)   
          ...   
      
      
   Chris   
      
      
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