From: sdcoonce@googlemail.com   
      
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   Hello,   
      
   I found code similar to the following in some client's codebase which   
   we had been asked to repair for new compilers, and was curious about   
   why this should compile and (seem to) work.  I was wondering if the use   
   of 'a' before initialization is really undefined behavior or just an   
   specified result.  Also, it seems intuitively to me that 'a' shouldn't   
   yet be in scope, though apparently it is.   
      
   I tried to find relavent paragraphs in the C++ standard but was unable   
   to find anything definitive.  Could someone who's better at reading the   
   standard than myself point me in the right direction?   
      
   //------------------------------------------   
   #include    
      
   using std::cout;   
   using std::endl;   
      
      
      
   int main(int argc, const char** argv) {   
      
      
      double a = a * 2.0;   
      cout << "a = " << a << "\n";   
      
      return 0;   
      
   }   
      
   //--------------------------------------------   
      
   In fact, I was suprised that the compilers (Windows VS2012) doesn't   
   automatically emit a warning for this case. With /Wall, it does --   
   but then there are hundreds of errors in standard header files.   
   I understand why we don't compile with /Wall.   
      
   Thanks,   
   Scott   
      
      
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