In article <2024May21.085224@mips.complang.tuwien.ac.at>,   
   Anton Ertl  wrote:   
      
   >Basically we have a multiplication of three factors: x, y, and 1/z;   
   >and the assumption is that the product of all three is in range, while   
   >there is one product of one of the factors that is out of range.   
   >   
   >It seems to me that this can be solved by sorting the three factors   
   >into a>b>c.  Then you can avoid the intermediate overflow by   
   >performing the computation as (a*c)*b.   
      
   Make that |a|>|b|>|c|   
   >- anton   
      
   Groetjes Albert   
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