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|    comp.lang.c    |    Meh, in C you gotta define EVERYTHING    |    243,242 messages    |
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|    Message 241,297 of 243,242    |
|    olcott to All    |
|    That HHH(DD) rejects its input as non-ha    |
|    11 Oct 25 15:33:14    |
   
   XPost: comp.theory, comp.lang.c++, comp.ai.philosophy   
   From: polcott333@gmail.com   
      
   That HHH(DD) correctly rejects its input on the   
   following basis is semantically entailed by the   
   following formal rubric list below this much more   
   human readable version.   
      
   Whether or not and to what degree it applies to   
   the halting problem is another different matter.   
      
   LLM systems are currently very good at semantic logical   
   entailment. When limited to this task they have no   
   opportunity for hallucination, thus seem to be quite   
   reliable as empirical testing has shown.   
      
   *This is the human readable form of the formal rubic*   
   *Clause AI, ChatGPT 4.0 and Grok fully understood this one*   
      
      
   Simulating Termination Analyzer HHH correctly simulates its input until:   
   (a) Detects a non-terminating behavior pattern:   
    abort simulation and return 0.   
   (b) Simulated input reaches its simulated "return" statement:   
    return 1.   
      
   typedef int (*ptr)();   
   int HHH(ptr P);   
      
   int DD()   
   {   
    int Halt_Status = HHH(DD);   
    if (Halt_Status)   
    HERE: goto HERE;   
    return Halt_Status;   
   }   
      
   int main()   
   {   
    HHH(DD);   
   }   
      
   What value should HHH(DD) correctly return?   
      
      
   *This is the beginning of the formal rubric*   
   *When one perfectly sticks to the rules then*   
   *there is only one possible result*   
      
   
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