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   comp.lang.c      Meh, in C you gotta define EVERYTHING      243,242 messages   

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   Message 242,106 of 243,242   
   olcott to Kaz Kylheku   
   Re: DD simulated by HHH and DD simulated   
   24 Nov 25 14:20:33   
   
   XPost: comp.theory, comp.lang.c++   
   From: polcott333@gmail.com   
      
   On 11/24/2025 1:30 PM, Kaz Kylheku wrote:   
   > On 2025-11-24, olcott  wrote:   
   >> On 11/24/2025 11:55 AM, Kaz Kylheku wrote:   
   >>> On 2025-11-24, olcott  wrote:   
   >>>> On 11/24/2025 10:32 AM, Kaz Kylheku wrote:   
   >>>>> On 2025-11-24, olcott  wrote:   
   >>>>>> On 11/22/2025 11:24 PM, Kaz Kylheku wrote:   
   >>>>>>> That's just the thing! If this were correctly implemented then in fact   
   >>>>>>> DD /wold be/ calling HHH1, using the name HHH.   
   >>>>>>>   
   >>>>>>   
   >>>>>> You are trying to get away with this lie   
   >>>>>> about the semantics of C?   
   >>>>>>   
   >>>>>> int main()   
   >>>>>> {   
   >>>>>>       HHH(DD);   
   >>>>>>       HHH1(DD);   
   >>>>>>       return 0;   
   >>>>>> }   
   >>>>>>   
   >>>>>> _main()   
   >>>>>> [000022c4] 55             push ebp   
   >>>>>> [000022c5] 8bec           mov ebp,esp   
   >>>>>> [000022c7] 6834220000     push 00002234 ; push DD   
   >>>>>> [000022cc] e833f3ffff     call 00001604 ; call HHH   
   >>>>>> [000022d1] 83c404         add esp,+04   
   >>>>>> [000022d4] 6834220000     push 00002234 ; push DD   
   >>>>>> [000022d9] e856f2ffff     call 00001534 ; call HHH1   
   >>>>>> [000022de] 83c404         add esp,+04   
   >>>>>> [000022e1] 33c0           xor eax,eax   
   >>>>>> [000022e3] 5d             pop ebp   
   >>>>>> [000022e4] c3             ret   
   >>>>>> Size in bytes:(0033) [000022e4]   
   >>>>>   
   >>>>> That's right; even if HHH and HHH1 are separately realized and given   
   >>>>> different adddresses, not recognized as identical by the compiler and   
   >>>>> not folded into one copy, in a correct implementation of your software,   
   >>>>> HHH(DD) and HHH1(DD) would behave as indistinguishable, mutually   
   >>>>> interchangeable operations.   
   >>>>>   
   >>>>> The problem is that you have logic which concludes that HHH1 != HHH (low   
   >>>>> level pointer comparison), they are different functions.   
   >>>>>   
   >>>>   
   >>>> Except when their input calls themself.   
   >>>   
   >>> That makes no difference.   
   >>>   
   >>   
   >> typedef int (*ptr)();   
   >> int HHH(ptr P);   
   >> int HHH1(ptr P);   
   >   
   > Please, don't post this repeated crap any more.   
   >   
      
   As long as you keep lying I will keep repeating it.   
   If five people from comp.lang.c confirm that you   
   are lying and I am correct then I will quit posting it.   
      
   typedef int (*ptr)();   
   int HHH(ptr P);   
   int HHH1(ptr P);   
      
   int DD()   
   {   
      int Halt_Status = HHH(DD);   
      if (Halt_Status)   
        HERE: goto HERE;   
      return Halt_Status;   
   }   
      
   int main()   
   {   
      HHH(DD);   
      HHH1(DD);   
   }   
      
   HHH simulates DD that calls HHH(DD)   
   that simulates DD that calls HHH(DD)...   
      
   HHH1 simulates DD that calls HHH(DD) that   
   returns to DD that returns to HHH1.   
      
      
   --   
   Copyright 2025 Olcott   
      
   My 28 year goal has been to make   
   "true on the basis of meaning" computable.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   

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