From: janis_papanagnou+ng@hotmail.com   
      
   On 2026-02-06 06:10, Keith Thompson wrote:   
   > Bart  writes:   
   >   
   >> If I compile this code with 'gcc -Wall -Wextra -Wpedantic':   
   >>   
   >>    #include    
   >>   
   >>    int main() {   
   >>        int a = -1;   
   >>        printf("%u", a);   
   >>    }   
   >>   
   >> it says nothing. The program displays 4294967295 instead of -1.   
      
   Yes. You instruct 'printf' with '%u' to interpret and display it   
   (the variable 'a') as unsigned. ('-1' is not an unsigned numeric   
   representation.) - I wonder what you are thinking here.   
      
   >   
   > The behavior is unsurprising.  The lack of a warning is very mildly   
   > inconvenient.   
      
   Indeed unsurprising. And I even don't see any inconvenience given   
   that even an initialized declaration of 'unsigned a = -1;' is not   
   considered a problem in "C". I rather learned that to be a useful   
   code pattern when programming in "C".   
      
   Janis   
      
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