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| comp.lang.fortran | Putting John Backus on a giant pedestal | 5,127 messages |
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| Message 4,700 of 5,127 |
| Steven G. Kargl to R Daneel Olivaw |
| Re: Is there a way in Fortran to designa |
| 03 Oct 24 15:07:41 |
From: sgk@REMOVEtroutmask.apl.washington.edu On Thu, 03 Oct 2024 14:45:31 +0200, R Daneel Olivaw wrote: > Lynn McGuire wrote: >> I need many of my integers to be integer*8 in my port to 64 bit. In >> C/C++ code, I can say 123456L to mean a long long value, generally 64 >> bit. Is there a corresponding way to do this in Fortran or am I stuck >> with: >> >> call xyz (1) >> >> subroutine xyz (ivalue) >> integer*8 ivalue >> ... >> return end >> >> must be: >> >> integer*8 ivalue >> ... >> ivalue = 1 >> call xyz (ivalue) >> > > This is not actually a Fortran issue as such, it's all about a specific > compiler (GNU Fortran). If we overlook the nonstandard type in the declaration, and agree that the compiler will accept 'integer*8', then the program is still invalid Fortran. It's technically not a Fortran issue. It is a programmer issue. -- steve --- SoupGate-Win32 v1.05 * Origin: you cannot sedate... all the things you hate (1:229/2) |
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