From: Danny@hyperspace.vogon.gov   
      
   Steven G. Kargl wrote:   
   > On Thu, 03 Oct 2024 14:45:31 +0200, R Daneel Olivaw wrote:   
   >   
   >> Lynn McGuire wrote:   
   >>> I need many of my integers to be integer*8 in my port to 64 bit.  In   
   >>> C/C++ code, I can say 123456L to mean a long long value, generally 64   
   >>> bit.  Is there a corresponding way to do this in Fortran or am I stuck   
   >>> with:   
   >>>   
   >>>       call xyz (1)   
   >>>   
   >>>       subroutine xyz (ivalue)   
   >>>       integer*8 ivalue   
   >>>       ...   
   >>>       return end   
   >>>   
   >>> must be:   
   >>>   
   >>>       integer*8 ivalue   
   >>>       ...   
   >>>       ivalue = 1   
   >>>       call xyz (ivalue)   
   >>>   
   >>   
   >> This is not actually a Fortran issue as such, it's all about a specific   
   >> compiler (GNU Fortran).   
   >   
   > If we overlook the nonstandard type in the declaration, and agree   
   > that the compiler will accept 'integer*8', then the program is   
   > still invalid Fortran.  It's technically not a Fortran issue.  It   
   > is a programmer issue.   
   >   
      
   Take a pragmatic approach, if that's the way the compiler wants you to   
   do it then do it that way.   
   Years ago I was converting a suite of programs from one OS/hardware   
   platform to another.  One program had serious problems because type   
   "real" had insufficient precision on the new machine, that machine   
   offered a compile option which meant "real" automatically meant "double   
   precision" and - after checking for "equivalence" and common" statements   
   - that's the way I went.  Problem solved.  This was back in the days of   
   Fortran IV but I don't think I've ever seen anyone assigning Hollerith   
   values to Real numbers so that was not a problem either.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)