From: johndoe64738@yahoo.com   
      
   > So if you keep your datagram under 576, it's guaranteed that the   
   > receiver will be able to reassemble it if fragmentation is necessary.   
      
   Thank you, but 576 - 20 - 8 = 548, thats 12 bytes more than the 536   
   magical packet size. Or maybe the 12 bytes are taken up because of the   
   possible IP fragmentation?   
      
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