XPost: comp.arch.embedded   
   From: m@rtij.nl.invlalid   
      
   On Sun, 06 Feb 2011 20:44:39 +0100, Morten Reistad wrote:   
      
   > So, if I assign [1:2:3:4::1/64] to an interface, the address   
   > [1:2:3:4:5::1] is assumed to be on that subnet, and you can use arp to   
   > get to it.   
      
   No you cannot. Arp is an IPv4 thingy, IPV6 uses multicast instead. But   
   otherwise your explanation is correct if we substitute either IPv4 for   
   IPv6, or multicast for arp.   
      
   HTH,   
   M4   
      
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