XPost: comp.arch.embedded   
   From: m@rtij.nl.invlalid   
      
   On Sun, 06 Feb 2011 21:36:39 +0000, glen herrmannsfeldt wrote:   
      
   > In comp.protocols.tcp-ip Martijn Lievaart  wrote:   
   >> On Sun, 06 Feb 2011 20:44:39 +0100, Morten Reistad wrote:   
   >   
   >>> So, if I assign [1:2:3:4::1/64] to an interface, the address   
   >>> [1:2:3:4:5::1] is assumed to be on that subnet, and you can use arp to   
   >>> get to it.   
   >   
   >> No you cannot. Arp is an IPv4 thingy, IPV6 uses multicast instead. But   
   >> otherwise your explanation is correct if we substitute either IPv4 for   
   >> IPv6, or multicast for arp.   
   >   
   > That isn't quite right.  IPv6 uses NDP instead of ARP, but it does   
   > pretty much the same thing.   
      
   Thanks for the correction.   
      
   M4   
      
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