From: mark_cruzNOTFORSPAM@hotmail.com   
      
   "Rick Jones"  wrote in message   
   news:kidij0$tii$2@usenet01.boi.hp.com...   
      
   [skip]   
   > I seem to recall something about the minimum IPv4 MTU being something   
   > like 68 bytes.  IP MTU is IP header + IP payload and does not include   
   > layer2 stuff.  And while the IP header is 20 bytes, I think there can   
   > be some number of IP options - perhaps 40 bytes worth.  Thus, after a   
   > 68 byte minimum IPv4 MTU, 20 bytes of IP header and 40 bytes of IP   
   > options, there are 8 bytes left for the L4 headers and data.   
   >   
   > From RFC 791 we have:   
   >   
   >    Every internet module must be able to forward a datagram of 68   
   >    octets without further fragmentation.  This is because an internet   
   >    header may be up to 60 octets, and the minimum fragment is 8 octets.   
      
   Thanks, this clarifies a lot.   
      
   Mark   
      
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