From: Uwe.Seimet@seimet.de   
      
   Hi all,   
      
   To Jean-Luc and everybody who contributed to the discussion of MiNT not   
   accepting a FAT32 partition of 4095 MB created by HDDRUTIL:   
   I finally checked HDDRUTIL's FAT size calculation and did not find   
   anything wrong, even though MiNT reports "FAT too small".   
      
   Let me summarize the calculation, so that you can comment on it:   
      
   When creating a FAT32 partition of 4095 MB HDDRUTIL allocates 8386528   
   sectors of 512 bytes for the FATs and the actual data area. 8174 sectors   
   are allocated for each FAT, which means that 8386528-2*8174=8370180   
   sectors remain for the actual data. There are 8 sectors per cluster,   
   which means that there are 8386528/8=1046272 data clusters. For each of   
   these 1046272 clusters a 32 bit FAT entry is required, which means that   
   1046272*4=4185088 bytes are needed per FAT. This is exactly what 8174   
   sectors per FAT amount to: 8174*512=4185088.   
      
   This calculation shows that the number of FAT sectors allocated by   
   HDDRUTIL is exactly the number of sectors needed.   
   If my calculation is right MiNT is wrong and should be fixed. If my   
   calculation is wrong please point out the error so that I can fix my code.   
      
   Best regards   Uwe   
      
   --   
   -----------------------------------------------------------------------   
      Dr. Uwe Seimet                                http://www.seimet.de/   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)