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|  Message 66  |
|  Wilfred van Velzen to Charles Pierson  |
|  Re: Error message  |
|  05 Feb 21 23:02:01  |
 
TID: FMail-lnx64 2.1.0.18-B20170815
RFC-X-No-Archive: Yes
TZUTC: 0100
CHRS: UTF-8 2
PID: GED+LNX 1.1.5-b20161221
MSGID: 2:280/464 601dc146
REPLY: 1:106/127 031409d9
Hi Charles,
On 2021-02-05 14:35:27, you wrote to All:
CP> I'm trying to make an RSS scraper to pull articles from RSS feeds and
CP> export them to text files, to be used either in my BBS bulletins or
CP> message areas
CP> I found a web page that supposedly does exactly this, however using the
CP> code and testing I get the Folliwing error:
CP> python scraping.py
CP> File "scraping.py", line 5
CP> def
CP> hackernews_rss('https://news.ycombinator.com/rss'):
CP> ^
CP> SyntaxError: invalid
CP> syntax
CP> The code is:
CP> # scraping function
CP> def hackernews_rss('https://news.ycombinator.com/rss'):
There should be a variable there between the (), not a constant in this
function definition.
CP> try:
CP> r = requests.get()
Is 'requests' defined of set somewhere? I don't see it.
CP> return print('The scraping job succeeded: ', r.status_code)
CP> except Exception as e:
CP> print('The scraping job failed. See exception: ')
CP> print(e)print('Starting scraping')
CP> hackernews_rss()
Here where you call it you can give the constant to the function, like:
hackernews_rss('https://news.ycombinator.com/rss')
CP> print('Finished scraping')
CP> Any idea what I flubbed?
Bye, Wilfred.
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