From: lotteryprediction@gmail.com   
      
   I would suggest each player could post two sets for the Fibonacci series for   
   later new competitions.   
   It can be seen that even if at least one set out of two generates a 3 in 11   
   till round 5, the chance of making profits would be still 100%.   
   However, when a player chooses to play 3 sets, he would have lost, even at   
   round 2 ( losing 190 euro) and would have lost more up to 1940 euro at round   
   5, unless he makes a 3 in 11 among 3 sets at Round 1, winning (1   
   800)-{165*3*1)}=800-495=305 euro.   
      
   For example, if MJ played two sets including his and Jerome's till round 5, he   
   would have still won.   
      
   (5*800)-{165*2*(1+1+2+3+5)}=4000-3960=40 euro   
      
   if MJ played three sets till round 5, he would have lost 1940 euro.   
   (5*800)-{165*3*(1+1+2+3+5)}=-4000-5940=- 1940   
      
   if Nan played his set and Leela's till round 2, he would have still won:   
   (1*800)-{165*2*(1+1)}=800-660=140 euro.   
      
   if Nan played three sets including Leela's and Alphazero's, he would have lost   
   190 euro.   
   (1*800)-{165*3*(1+1)}=800-990= - 190 euro   
      
   The sooner you make a 3 in 11, the more prize you would won.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)