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|    rec.arts.sf.science    |    Real and speculative aspects of SF scien    |    45,986 messages    |
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|    Message 44,883 of 45,986    |
|    Luke Campbell to MrAnderson    |
|    Re: Coilgun projectile velocities in spa    |
|    15 Mar 17 16:39:58    |
      From: lwcamp@gmail.com              On Wednesday, March 15, 2017 at 3:09:09 PM UTC-7, MrAnderson wrote:       > Hi, Mr Campbell!       > How is this is possible? The meteors, burning satellites, go well beyond 100       their lenght when in atmosphere I think.               That's because they start to disintegrate up in the mesosphere, where the air       density is 10 million to 10 trillion times less than at sea level.               > But if that's true, are there any heat shield ways to overcome this?               It's not a matter of heat shielding, but of material strength. At high       speeds, the ram pressure of pushing through the air overcomes the material       strength of the projectile, and it breaks up. You need heat shielding, too,       but it needs to be both strong        and refractory.              > Also, wouldn't such thing make kinetic bombardment idiotic?              If the initial ablation part of the descent causes the projectile to slow down       to where it is no longer being ablated, then you have a perfectly serviceable       projectile that is still moving at 1 to 4 km/s when it hits the ground.              > On penetration, why is that? The kinetic energy of 2 km/s rod is smaller       than of 50 km/s rod, so why would it be this way?              Kinetic energy doesn't give you penetration.              Consider the case where the projectile is moving so fast that the dynamic       pressure at the interface between the projectile and the target greatly       exceeds the material strength. Call the speed of the impact V. Imagine that       you are moving along with this        interface layer, watching as the projectile burrows into the target. Call the       speed at which the interface layer propagates into the target U. From this       vantage point, you see the target material coming from the right with speed U,       and the projectile        material coming from the left at speed V-U, creating a stationary region where       they collide into each other. The dynamic pressure is given by Bernoulli's       principle, and is the fluid's density times the square of its speed (where,       because we can neglect        material strength, both the projectile and the target can be considered       fluids). Since the interface is stationary, the pressures must be equal. So       (target density) x (V-U)^2 = (material density) x U^2. You can see that the       rate at which the        projectile is being ablated (the (V-U) term) is related to the rate at which       the target is being penetrated (the U term) by the ratio of the square roots       of their densities. Multiply this ratio by the length, and you find that the       distance the target is        penetrated is the length of the projectile times the square root of       (projectile density)/(target density).              Thus, at high speeds where material strength is irrelevant, the distance of       penetration of a long rod is constant, and has no dependence on speed.              If you use a very strong material (like tungsten carbide), then at around 1.5       to 2 km/s you can be in a regime where the strength of the projectile still       matters but the strength of the target does not. This increases the       penetration of the projectile.        If you start going faster than this, the superior strength of the projectile       no longer comes into play and the penetration decreases.              There are some second-order effects that can introduce some speed dependence       to penetration but for long rods they are small.              Luke              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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