From: daellis94@gmail.com   
      
   I tried a quick calculation using some numbers available on Wikipedia's page   
   on Nuclear Fusion.  One of the tables describing conditions for various   
   reactions places an ideal plasma temperature for helium-3-deuterium fusion at   
   58 kiloelectronvolts, and    
   the combined charged particle energy released from said reaction works out to   
   18.3 megaelectronvolts--to use the same units, 18 300 kiloelectronvolts.     
      
   Treating 58 keV as the energy required to ignite the fusion reaction, I simply   
   divided 18 300 by 58 (I'm really hoping I've remembered the temperature   
   correctly, otherwise I will look like a moron) and found that this would, in   
   theory, work out to a Q of    
   just over 315.     
      
   I have no real sense for how far this might be from the true theoretical   
   limit, but it seems like a decent guess on my part.   
      
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