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|    rec.arts.sf.science    |    Real and speculative aspects of SF scien    |    45,986 messages    |
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|    Message 45,672 of 45,986    |
|    eripe to Sjouke Burry    |
|    Re: earth space elevator, moon, tilt    |
|    17 Sep 19 18:14:07    |
      From: eripe.dk@gmail.com              On Tuesday, September 17, 2019 at 10:43:47 AM UTC+7, Sjouke Burry wrote:       > On 17.09.19 2:03, eripe wrote:       > > On Tuesday, September 17, 2019 at 5:09:00 AM UTC+7, Bob Jenkins wrote:       > >> Space elevators won't work. Well maybe they will but they're more       complicated than we've been thinking.       > >>       > >> A space elevator would be anchored at one point on earth, usually over       the ocean on the equator, then would extend straight up to about 1/5th the       distance to the moon.       > >>       > >> A minor overlooked matter is the moon. It's 1/81th the mass of the       earth, and on average 10x further from the elevator than the earth, so the       elevator would be pulled up at 1/8000th its weight when the moon is overhead.        So the connection to earth        has to be strong enough to resist a force of 1/8000th the elevator's total       mass pulling up. Like tides, it'll be 1/8000th heavier when the moon is       opposite the elevator, so it's more like 1/4000th fluctuation daily.       > >>       > >> But the major overlooked matter is that the earth's equator is not       aligned with the moon's orbit. It's off by 18 to 29 degrees. Two issues.       > >>       > >> 1. The elevator's orbit wants to be in the plane of the moon's orbit,       because the moon tugs it that way once a day. On planets without a moon, the       sun will have a similar effect. The plane of the earth's orbit around the sun       and the plane of the        moon's orbit around the earth are pretty close, off by about 5 degrees. If       the elevator isn't in the moon's plane, it'll fall towards it, and keep       falling past it then fall back, oscillating back and forth. "Precession."        From earth this looks like        tilting north, then south, then back to north, once a day. If you start with       an elevator pointed up, after a few years it'll have fallen 2*29 degrees to       the side, forming a 32 degree angle with the ground, then it'll rise back to       straight up, back and        forth. If you want to prevent it from precessing, you have to actively push       it sideways, which is a thrust of about 1/100000th the elevator's mass times g       all the time. I can't see doing that. So instead you'd build the elevator in       the moo       > n's orbital plane in the first place, and it would tip north and south daily       by 18 to 29 degrees.       > >>       > >> 2. The elevator no longer goes straight up from the nearest point on       earth: the connection oscillates north and south from the nearest point       between -18 to -29 and 18 to 29 degrees daily. This implies a change of up to       800km of elevator length        twice daily. Perhaps you could spool it up then reel it out again. You could       drive a power plant off of reeling it out. The elevator cable will be moving       pretty fast: 800km in 12 hours is an average of 66km/hour. Alternatively, you       could keep the        elevator connection fixed, just tugging harder when the attachment point is       pulling in and tugging less when the attachment point is going out.       > >>       > >> Any pictures of a space elevator going straight up from earth are as       wrong as a stopped clock: they're only right for an instant twice daily.       > >       > > The force from the moon is tiny compared to the self correcting force to       the rotating plane. If the station is 1° off that plane it will be pulled       back by a force of sin(1)= 1,7% of its mass.       > > The moon can only make it wobble a widdle.       > >       > There is no cable able to carry its own weight , and a few percents will        > make       > no difference whatsoever.       > Any cable of any type of matter will break.                     Lets see,        Force is L A g rho        Strength needed is A s       so s = L g rho              L = 40.000.000 m       rho = 2200 kg/m3 (graphene)       g = 4 m/s^2 (best guess)              = 352 GPa              Graphene has a strength of 130 GPa so yes, you would have to taper the       structure to make it work.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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