XPost: rec.arts.sf.movies   
   From: j.clarke.873638@gmail.com   
      
   In article <%37wx.138800$pi.32741@fx47.am4>, {bap}@gamma.shrdlu.com   
   says...   
   >   
   > On 2015-08-01, J. Clarke  wrote:   
   > >   
   > >> Note that I was specifically referring to the power efficiency,   
   > >> (an ideal photon drive requires 300MW/N, the claimed figure for the EM   
   > >> Drive is about 1GW/N).   
   > >   
   > > And how much does kerosene require per newton?   
   >   
   > It's irrelevant to the discussion. If (admittedly a big if) the drive works   
   > as described then it isn't intended for roles that a reaction drive can   
   > fill. The quantity of energy it uses to achieve a given amount of force is   
   > not a useful measure of efficiency. Efficiency is a ratio between cost and   
   > benefit achieved. The drive as described produces thrust without expending   
   > mass. Its cost is therefore zero and if it generates any thrust  its   
   > efficiency is infinite.   
      
   You know that and I know that but the bright boy who was on about energy   
   per newton doesn't seem to get it.   
      
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