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|    rec.audio.tubes    |    Tube-based amplifiers... that go to 11    |    52,877 messages    |
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|    Message 51,145 of 52,877    |
|    Ian Bell to Ian Iveson    |
|    Re: SE Headphones Amp    |
|    06 Oct 10 11:04:05    |
      From: ruffrecords@yahoo.com              Ian Iveson wrote:       >> So my question is, how does the inductance vary with (dc)       >> current. If it measures higher with lower dc current then       >> if I use a 10W instead of a 5W but with a lower dc       >> current, do I get even higher inductance because of the       >> lower current?       >       > This isn't a simple question, IIRC from longago posts. I       > venture the following expecting a tongue-lashing.       >       > The inductance varies with the slope of the BH curve. If you       > look at one common, DC depiction of that curve, it appears       > as a sigmoid, shallow at the zero crossing because the       > magnetic domains exhibit what you might call stiction,       > becoming steeper, and then shallow again as the majority of       > domains reach their elastic limit, and some reach the yield       > point.       >       > The yielding dissipates power, resulting in hysteresis.       > Consequently, for AC, the sigmoid becomes a loop, steepest       > at the zero crossing, and shallow at both extremes of its       > variation. What's more, any AC signal will generate a       > sigmoid, with the magnetic bias affecting how flat or steep       > the sigma-shaped loop is, according to where its centre is       > on to the DC BH curve.       >       > Break for ridicule.       >       > Now, it seems from the DC curve that inductance should be       > zero as B crosses the H axis. Much nonsense arises from this       > interpretation. In fact, for pure AC the curve is steepest       > there, both on the upward and downward journey.       >       > However the sigmoid is flattish for small AC signals, so the       > mean inductance is lowish. Then it gets steeper as the       > signal increases, so the mean inductance rises, and then       > begins to flatten out at its extremes and the inductance       > falls again, as the core saturation approaches.       >       > Still with me?       >       > Add DC and small signals see a higher inductance, but the       > average inductance for larger signals doesn't increase very       > much, especially if the signal results in the core getting       > to the sharper curve approaching saturation.       >       > I would have thought that the great benefit of using a       > transformer rated for high DC current, assuming the same       > rated inductance, would be that it gives you greater       > separation between roll-off and saturation. That means you       > can use more feedback to extend its bass range at a given       > max signal. Alternatively, some designs bias the SE       > transformer and deliberately oversize it, to avoid the bass       > disappearing at small signal levels. So they say, I think.       >       > So, the answer is: yes and no.       >       > Ian       >       >       > "Ian Bell" |
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