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|    sci.electronics.basics    |    Elementary questions about electronics    |    72,318 messages    |
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|    Message 71,161 of 72,318    |
|    AK to Cursitor Doom    |
|    Re: What determines a low leakage capaci    |
|    18 May 19 11:51:26    |
      From: scientist77017@gmail.com              On Saturday, May 18, 2019 at 1:03:05 PM UTC-5, Cursitor Doom wrote:       > On Sat, 18 May 2019 10:50:16 -0700, AK wrote:       >        > > So it looks like even with a laser shining and someone breaks the beam,       > > it may not sound if the light level is high enough.       >        > Dump the LDR and use a photodiode instead.       >        >        >        >        >        > --        > This message may be freely reproduced without limit or charge only via        > the Usenet protocol. Reproduction in whole or part through other        > protocols, whether for profit or not, is conditional upon a charge of        > GBP10.00 per reproduction. Publication in this manner via non-Usenet        > protocols constitutes acceptance of this condition.              Would this work?              Silicon Photodiode with Daylight Filter       PIN Photodiode Chip, BPW34       Features       Photocurrent: 80 µA (? 50 µA)       Reverse voltage: 32V       Forward voltage @ current: 1.3V @ 80uA       Total power dissipation: 150mW       Spectral sensitivity: 0.62 A/W       Wavelength of max. sensitivity: 850nm       Radiant sensitive area: 7.0mm²       Half angle: ±60 degrees       Short switching time: 20ns typ.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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