From: nobody@nowhere.com   
      
   On 6/7/2020 3:06 AM, Steve Wolf wrote:   
   > That's great .   
   > Can you explain it a bit. I'd like to understand it somewhat . You have   
   created what appears to me to be a rectifier but on one line and then bypassed   
   that with led.   
   >   
   >   
   > Regards.   
   >   
      
   Ralph Mowery's explanation is correct, except that when there's a   
   considerable load on a silicon diode, the voltage drop is more   
   than the oft-quoted 0.6V. It's more like 1V and two of them is   
   about right to light up a red or amber LED. It won't work well   
   with green or white LEDs.   
      
   The 1V or so drop is not constant. It varies with the AC wave, so   
   will the instantaneous brightness at any given moment. What your   
   eyes see is the average.   
      
   The average current, and therefore the apparent brightness, will   
   also vary with the load current - from a fraction of a milliamp   
   to some mAs.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)