From: nobody@nowhere.com   
      
   On 6/7/2020 12:09 PM, Pimpom wrote:   
   > On 6/7/2020 3:06 AM, Steve Wolf wrote:   
   >> That's great .   
   >> Can you explain it a bit. I'd like to understand it somewhat . You have   
   created what appears to me to be a rectifier but on one line and then bypassed   
   that with led.   
   >>   
   >>   
   >> Regards.   
   >>   
   >   
   > Ralph Mowery's explanation is correct, except that when there's a   
   > considerable load on a silicon diode, the voltage drop is more   
   > than the oft-quoted 0.6V. It's more like 1V and two of them is   
   > about right to light up a red or amber LED. It won't work well   
   > with green or white LEDs.   
   >   
   > The 1V or so drop is not constant. It varies with the AC wave, so   
   > will the instantaneous brightness at any given moment. What your   
   > eyes see is the average.   
   >   
   > The average current, and therefore the apparent brightness, will   
   > also vary with the load current - from a fraction of a milliamp   
   > to some mAs.   
   >   
      
   BTW, you can add several more LEDs in parallel with the first for   
   better visibility if you like, preferably each with its own   
   series resistor. You can also add them in the opposite direction.   
      
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