XPost: comp.theory, comp.ai.philosophy, comp.software-eng   
   From: flibble@reddwarf.jmc   
      
   On Fri, 16 Jul 2021 09:36:15 -0500   
   olcott wrote:   
      
   > On 7/16/2021 8:39 AM, Mr Flibble wrote:   
   > > On Fri, 16 Jul 2021 14:34:54 +0100   
   > > Ben Bacarisse wrote:   
   > >    
   > >> Mr Flibble writes:   
   > >>    
   > >>> All extant halting problem proofs appear to be predicated on a   
   > >>> misunderstanding of the following contradiction:    
   > >>   
   > >> I don't think you've read any actual proofs, let along all of them.   
   > >> Why you would even say such a thing?   
   > >>    
   > >>> Suppose T[R] is a Boolean function taking a routine   
   > >>> (or program) R with no formal or free variables as its   
   > >>> argument and that for all R, T[R] — True if R terminates   
   > >>> if run and that T[R] = False if R does not terminate.   
   > >>> Consider the routine P defined as follows   
   > >>>   
   > >>> rec routine P   
   > >>> §L :if T[P] goto L   
   > >>> Return §   
   > >>>   
   > >>> If T[P] = True the routine P will loop, and it will   
   > >>> only terminate if T[P] = False. In each case T[P] has   
   > >>> exactly the wrong value, and this contradiction shows   
   > >>> that the function T cannot exist.   
   > >>>   
   > >>> [Strachey 1965]   
   > >>>   
   > >>> T is indeed unable to decide P but for the wrong reason: T[P] is   
   > >>> recursive    
   > >>   
   > >> T[P] is not recursive. Maybe you don't understand what the CPL   
   > >> means?    
   > >    
   > > Of course it is recursive, such is obvious even to the casual reader   
   > > who is unfamiliar with the CPL language (a clue: read the paragraph   
   > > before the definition of P again).   
   > >    
   >    
   > "Recursive" has a very different meaning in computer science than it    
   > does in software engineering.   
      
   By "recursion" I am referring to a function that calls itself either   
   directly or indirectly; in the case of [Strachey 1965] the recursion is   
   indirect:   
      
   T[P] -> P -> T[P] -> P -> T[P] ... ...   
      
   /Flibble   
      
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