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   sci.math.symbolic      Symbolic algebra discussion      10,432 messages   

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   Message 10,385 of 10,432   
   Ben Bacarisse to clicliclic@freenet.de   
   Re: when wolfram alpha fails   
   28 Feb 24 01:51:17   
   
   XPost: sci.math   
   From: ben.usenet@bsb.me.uk   
      
   "clicliclic@freenet.de"  writes:   
      
   > James Cloos schrieb:   
   >>   
   >> > Assuming that "%CF%80" in the URL represents the imaginary unit #i,   
   >> > your symbolic input expression reads:   
   >>   
   >> I haven't followed this thread closely, but that got me curious.   
   >> cf 80 is the utf8 for U+03C0 GREEK SMALL LETTER PI.   
   >>   
   >   
   > Thanks. Now we need to know if the GREEK SMALL LETTER PI is supposed to   
   > equal the ASCII string "pi" appearing a few characters later in the   
   > URL. If the two are equal, the expression becomes:   
   >   
   > 1/SQRT(2)*SIN((1/8   
   >  - 6*ATAN(1/4*(-20 - 12*SQRT(3)) - SQRT(7*(7 + 4*SQRT(3)))   
   >  + SQRT(102 + 58*SQRT(3) + 142*SQRT(7/(7 + 4 + SQRT(3)))   
   >  + 82*SQRT(21/(7 + 4*SQRT(3)))))/pi)*2*pi)   
   >   
   > and evaluates numerically to:   
   >   
   > -0.5445033022   
      
   If I take what the OP passed to Wolfram Alpha and add in the missing   
   operators I get this:   
      
   (1/sqrt(2))*sin((1/8-((6*(atan(1/4*(-20-12*sqrt(3))-sqrt(7*(7+4*   
   qrt(3)))+sqrt(102+58*sqrt(3)+142*sqrt(7/(7+4*sqrt(3)))+82*sqrt(2   
   /(7+4*sqrt(3)))))))/pi))*2*pi)   
      
   Passing that to a calculator program I get:   
      
   ~0.33071891388307382398   
      
   which is pretty close to SQRT(7)/8.   
      
   --   
   Ben.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   

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