From: nma@12000.org   
      
   On 11/13/2013 10:49 PM, Albert Rich wrote:   
      
      
   > Rubi extracts the piecewise constant leaving the simpler integrand   
   f(x)^a/g(x)^a.   
   >Unfortunately in this case, it is not integrable, but progress has been made.   
   >   
   > Hope this explanation helps.   
   >   
   > Albert   
   >   
      
   Thank you. I was looking at this post   
      
   http://math.stackexchange.com/questions/566138/a-closed-form-for   
   int-0-infty-left-frac2-x-3-xx-rightadx-a-notin   
      
   where the claim is that there is closed form for "a" integers, a>0.   
      
   integrand  = ((2^(-x) - 3^(-x))/x)^a   
      
   integrated from x=0 to x=infinity.   
      
   So since Rubi does indefinite integration only, I wanted to see if   
   it will evaluate it, then I can afterwords evaluate it at the   
   limits and see the result.   
      
   --Nasser   
      
   --- SoupGate-Win32 v1.05   
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