From: &noreply@axelvogt.de   
      
   On 01.03.2014 05:33, Richard Fateman wrote:   
   > I don't consider a solution that includes   
   > Si, Ci, or hypergeometric functions as a solution   
   > in closed form in terms of elementary functions.   
   >   
   > Unless there is no way of expressing the answer in   
   > terms of elementary functions.   
   ...   
      
   Using Cosinus Fourier one can achieve it in terms of elementary functions.   
      
   F:= (a,t) -> -1/8*Pi*a/sqrt(-a)*exp(-sqrt(-a)*t), the transform of a/(a-x^2)/4   
      
   Then it is 2*Sum( F(a, 4)/8 + F(a, 2)/2 + F(a, 0)*3/8), a),   
   where 'a' runs through the four solutions of z^2+1 = 0.   
      
   Or more nicely: Pi/32*Sum((exp(-4*sqrt(-a))+4*exp(-2*sqrt(-a))+3)*sqrt(-a), a)   
      
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