From: &noreply@axelvogt.de   
      
   On 01.03.2014 12:12, Axel Vogt wrote:   
   > On 01.03.2014 05:33, Richard Fateman wrote:   
   >> I don't consider a solution that includes   
   >> Si, Ci, or hypergeometric functions as a solution   
   >> in closed form in terms of elementary functions.   
   >>   
   >> Unless there is no way of expressing the answer in   
   >> terms of elementary functions.   
   > ...   
   >   
   > Using Cosinus Fourier one can achieve it in terms of elementary functions.   
   >   
   > F:= (a,t) -> -1/8*Pi*a/sqrt(-a)*exp(-sqrt(-a)*t), the transform of   
   a/(a-x^2)/4   
   >   
   > Then it is 2*Sum( F(a, 4)/8 + F(a, 2)/2 + F(a, 0)*3/8), a),   
   > where 'a' runs through the four solutions of z^2+1 = 0.   
   >   
   > Or more nicely: Pi/32*Sum((exp(-4*sqrt(-a))+4*exp(-2*sqrt(-a))+3)*sqrt(-a),   
   a)   
      
   Typo: read as "where 'a' runs through the four solutions of z^4 + 1 = 0"   
   (and one can replace "-a" by "a" in the final formula).   
      
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