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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 8,515 of 10,432    |
|    Nasser M. Abbasi to All    |
|    Re: when is sqrt(a/b) not the same as sq    |
|    01 Mar 14 15:28:12    |
      From: nma@12000.org              On 3/1/2014 3:19 PM, Nasser M. Abbasi wrote:              Opss, sorry, forgot to put the sqrt(1) in there in all       the examples! I was just using (1).              Let me try again. Please ignore the first post. Here it is again:              was looking at a thread in Maple group. I was surprised that Maple       does not consider Sqrt[1/Sin[a]] the same as Sqrt[1]/Sqrt[Sin[a]]]       for all a.              I have always thought that sqrt(a/b) and sqrt(a)/sqrt(b) are       exactly the same              Mathematica simplifies this to zero with no assumptions:              Simplify[Sqrt[1/Sin[a]] - Sqrt[1]/Sqrt[Sin[a]]]        (* 0 *)              Maxima:              (%i6) fullratsimp( sqrt(1/sin(a)) - sqrt(1)/sqrt(sin(a)));       (%o6) 0              While Maple will not              simplify(sqrt(1/sin(alpha))-sqrt(1)/sqrt(sin(alpha)));              The above returns unevaluated. But when telling Maple to       assume sin(alpha)>0 (thanks to the hint on the Maple group)       only then it returns zero:              simplify(sqrt(1/sin(alpha))-sqrt(1)/sqrt(sin(alpha))) assuming sin(alpha)>0;       (* 0 *)              Is Mathematica and Maxima wrong here? or is Maple wrong?              --Nasser              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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