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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 8,550 of 10,432    |
|    Axel Vogt to Nasser M. Abbasi    |
|    Re: integrating dirac delta over the rea    |
|    04 Apr 14 21:43:24    |
   
   From: &noreply@axelvogt.de   
      
   On 02.04.2014 21:25, Nasser M. Abbasi wrote:   
   > What should CAS do when asked to integrate a dirac delta   
   > over the real line when its argument is never zero on   
   > the real line?   
   >   
   > There is no solution for 2-cos(t)=0 on real line.   
   >   
   > Maple 18:   
   > int( Dirac(2-cos(t)),t=-infinity..infinity);   
   > =========> unevaluated   
   >   
   > Mathematica 9.01   
   > Integrate[DiracDelta[2 - Cos[t]], {t, -Infinity, Infinity}]   
   > =======> 0   
   >   
   > What does your CAS produce? Another different behavior   
   >   
   > Maple:   
   > int( Dirac(I*t),t=-infinity..infinity);   
   > ======> 1   
   >   
   > and no Mathematica's turn to return unevaluated answer   
   >   
   > Integrate[DiracDelta[I t], {t, -Infinity, Infinity}]   
   > =====> remains unevaluated   
   >   
   >   
   > --Nasser   
      
   I am quite rusty on that. But:   
      
   Are you sure that your inputs make a mathematical sense   
   and what would you expect as answer (especially the 1st)?   
      
   Be aware that Dirac is not a function and it is not quite   
   trivial to see what is F°g for distribution F and fct g.   
      
   That may be a reason why Maple refuses an answer.   
      
   For the 2nd the answer is correct, g = some constant.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   
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