Forums before death by AOL, social media and spammers... "We can't have nice things"
|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
[   << oldest   |   < older   |   list   |   newer >   |   newest >>   ]
|    Message 8,551 of 10,432    |
|    dwelz@web.de to All    |
|    variable elimination from polynomial sys    |
|    05 Apr 14 19:49:11    |
      Maybe you can do this faster than Derive 6.10. I want to eliminate the       two variables x1, x2 from the three polynomial equations              2*x1^3*x2*(4*x2^2 - 3*(4*x4^2 + 1)) - x1^2*(12*x2^4 + 3*x2^2*(24*x3*x4 -       24*x4^2 - 1) - 6*x3*x4*(4*x4^2 + 3) + 12*x4^4 + 3*x4^2 - 2) +       6*x1*x2*(x2^4 - 2*x2^2*(2*x3^2 - 8*x3*x4 + 5*x4^2) + 3*x3^2*(4*x4^2 + 1)       - 2*x3*x4*(8*x4^2 + 1) + 5*x4^4) - x2^6 + 3*x2^4*(4*x3^2 - 10*x3*x4 +       5*x4^2) + 3*x2^2*(8*x3^3*x4 - x3^2*(24*x4^2 + 1) + 20*x3*x4^3 - 5*x4^4)       - 2*x3^3*x4*(4*x4^2 + 3) + x3^2*(12*x4^4 + 3*x4^2 - 2) - 6*x3*x4^5 +       x4^6 = 0              - 2*(x1^3*x4*(12*x2^2 - 4*x4^2 - 3) + 3*x1^2*x2*(4*x2^2*(x3 - 2*x4) -       3*x3*(4*x4^2 + 1) + x4*(8*x4^2 + 1)) - x1*(3*x2^4*(4*x3 - 5*x4) +       3*x2^2*(12*x3^2*x4 - x3*(24*x4^2 + 1) + 10*x4^3) - 3*x3^2*x4*(4*x4^2 +       3) + x3*(12*x4^4 + 3*x4^2 - 2) - 3*x4^5) + x2*(x3 - x4)*(3*x2^4 -       2*x2^2*(2*x3^2 - 10*x3*x4 + 5*x4^2) + 3*(x3^2*(4*x4^2 + 1) - 4*x3*x4^3 +       x4^4))) = 0              x2^2 + x4^2 - 2 = 0              Thus I started GROEBNER_BASIS([lhs1, lhs2, lhs3], [x1, x2, x3, x4]) on       Derive, where lhs1, lhs2, lhs3 are the left-hand sides of the three       equations; the computation is still running. However, I am interested       only in the basis elements not involving x1 and x2.              Thanks,              Martin.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
[   << oldest   |   < older   |   list   |   newer >   |   newest >>   ]
(c) 1994, bbs@darkrealms.ca