From: nma@12000.org   
      
   On 6/26/2014 4:47 AM, clicliclic@freenet.de wrote:   
      
   > Actually, I didn't mean to split the integrand into sooooo many parts;   
      
   Ok, But more parts, means each part is smaller in leaf count. Hence   
   it should be easier for a CAS to solve, I would have thought. So   
   in this case, the more parts, the better. One pay extra waiting   
   time for easier to solve pieces. At least that is what I expected to   
   happen ;)   
      
   > what I had in mind was to separate the 9+9 logarithms into 9 terms of   
   > 1+1 logarithm (pairing with the corresponding logarithm from the other   
   > group serves to keep the integral real), with a tenth term formed by the   
   > non-logarithmic remainder. Thus, my second integral covers the (easy to   
   > integrate) full remainder, and my third integral the first (relatively   
   > hard to integrate) logarithm from each group of nine.   
   >   
   > Martin.   
   >   
      
   Will try again and see what I can do.   
   regards,   
      
   --Nasser   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)