"Nasser M. Abbasi" schrieb:   
   >   
   > On 6/26/2014 4:47 AM, clicliclic@freenet.de wrote:   
   >   
   > > Actually, I didn't mean to split the integrand into sooooo many parts;   
   >   
   > Ok, But more parts, means each part is smaller in leaf count. Hence   
   > it should be easier for a CAS to solve, I would have thought. So   
   > in this case, the more parts, the better. One pay extra waiting   
   > time for easier to solve pieces. At least that is what I expected to   
   > happen ;)   
   >   
   > > what I had in mind was to separate the 9+9 logarithms into 9 terms of   
   > > 1+1 logarithm (pairing with the corresponding logarithm from the other   
   > > group serves to keep the integral real), with a tenth term formed by the   
   > > non-logarithmic remainder. Thus, my second integral covers the (easy to   
   > > integrate) full remainder, and my third integral the first (relatively   
   > > hard to integrate) logarithm from each group of nine.   
   > >   
   >   
   > Will try again and see what I can do.   
   >   
      
   It does not matter for the non-logarithmic part of the integrand, but   
   with the logarithmic terms there is the danger that the integrals are no   
   longer elementary if the algebraic prefactor is taken apart. I just do   
   not know as I did not investigate this point.   
      
   Martin.   
      
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