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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Collecting all different root factors in    |
|    12 Dec 15 22:40:04    |
      From: ivgroups@onlinehome.de              Hallo,              using Maple, I have an expression ( a[1]^(1/c) + a[2]^(1/c) + ... +       a[n]^(1/c) )^m whereby c, n and m are given positive integers. I type expand       and simplify/symbolic. How can I bracket out all root terms and collect all       summands with the same root factors? My target is to count the number of       *different* roots in the expression.              Example:       For c=3, n = 3 and m = 7, it is not enough to factor out a[1]^(1/3),       a[2]^(1/3), a[3]^(1/3) and its combinations. We have to factor out also the       powers with the exponent 2/3 and their combinations. That are all powers       with exponents e where (e mod c) <> 0.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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