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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 9,000 of 10,432    |
|    clicliclic@freenet.de to Axel Vogt    |
|    Re: computer brains wanted    |
|    13 Mar 16 18:51:11    |
      Axel Vogt schrieb:       >       > On 06.03.2016 08:13, clicliclic@freenet.de wrote:       > >       > > Let a,b,c,h,k be real numbers. Can the following be expressed more       > > compactly, perhaps by means of Cylindrical Algebraic Decomposition?       > >       > > h>=0 AND k>=0 AND ((2*a*b*c+k*(b^2-a^2)+b*(a^2+b^2)>=0 AND b<=0)       > > OR ((2*a*b*c+k*(b^2-a^2)+b*(a^2+b^2)<=0 AND a>=0)       > > AND (2*b*c*(a-h)-h^2*(k+b)+2*a*h*k+k*(b^2-a^2)+b*(a^2+b^2)<=0       > > AND a-h<=0) AND b+k>=0) OR (2*c*a*b+k*(b^2-a^2)+b*(a^2+b^2)<=0       > > AND 2*b*c*(a-h)-h^2*(k+b)+2*a*h*k+k*(b^2-a^2)+b*(a^2+b^2)>=0       > > AND b>=0))       >       > I would write (0 <= h and 0 <= k and (T1 or T2 or T3)) where       >       > T1 := 0 <= 2*a*b*c+k*(-a^2+b^2)+b*(a^2+b^2) and b <= 0       > T2 := 2*a*b*c+k*(-a^2+b^2)+b*(a^2+b^2) <= 0 and 0 <= a and       > 2*b*c*(a-h)-h^2*(k+b)+2*a*h*k+k*(-a^2+b^2)+b*(a^2+b^2) <= 0 and       > a-h <= 0 and 0 <= k+b       > T3 := 2*a*b*c+k*(-a^2+b^2)+b*(a^2+b^2) <= 0 and       > 0 <= 2*b*c*(a-h)-h^2*(k+b)+2*a*h*k+k*(-a^2+b^2)+b*(a^2+b^2) and       > 0 <= b       >       > and now abbreviate by r = 2*a*b*c+k*(b^2-a^2)+b*(a^2+b^2) to shorten       > it.       >       > And perhaps re-arrange according to 0 <= a resp 0 <= b.       >       > But may be you want something different.              Yes, I was hoping for something deeper than merely chopping and       abbreviating: different polynomials in a simplified overall structure.       But I suppose that Maple doesn't offer CAD, or that CAD is of no help       here.              Thanks for the suggestion,              Martin.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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