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   sci.math.symbolic      Symbolic algebra discussion      10,432 messages   

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   Message 9,000 of 10,432   
   clicliclic@freenet.de to Axel Vogt   
   Re: computer brains wanted   
   13 Mar 16 18:51:11   
   
   Axel Vogt schrieb:   
   >   
   > On 06.03.2016 08:13, clicliclic@freenet.de wrote:   
   > >   
   > > Let a,b,c,h,k be real numbers. Can the following be expressed more   
   > > compactly, perhaps by means of Cylindrical Algebraic Decomposition?   
   > >   
   > > h>=0 AND k>=0 AND ((2*a*b*c+k*(b^2-a^2)+b*(a^2+b^2)>=0 AND b<=0)   
   > >   OR ((2*a*b*c+k*(b^2-a^2)+b*(a^2+b^2)<=0 AND a>=0)   
   > >   AND (2*b*c*(a-h)-h^2*(k+b)+2*a*h*k+k*(b^2-a^2)+b*(a^2+b^2)<=0   
   > >   AND a-h<=0) AND b+k>=0) OR (2*c*a*b+k*(b^2-a^2)+b*(a^2+b^2)<=0   
   > >   AND 2*b*c*(a-h)-h^2*(k+b)+2*a*h*k+k*(b^2-a^2)+b*(a^2+b^2)>=0   
   > >   AND b>=0))   
   >   
   > I would write (0 <= h and 0 <= k and (T1 or T2 or T3)) where   
   >   
   > T1 := 0 <= 2*a*b*c+k*(-a^2+b^2)+b*(a^2+b^2) and b <= 0   
   > T2 := 2*a*b*c+k*(-a^2+b^2)+b*(a^2+b^2) <= 0 and 0 <= a and   
   >        2*b*c*(a-h)-h^2*(k+b)+2*a*h*k+k*(-a^2+b^2)+b*(a^2+b^2) <= 0 and   
   >        a-h <= 0 and 0 <= k+b   
   > T3 := 2*a*b*c+k*(-a^2+b^2)+b*(a^2+b^2) <= 0 and   
   >        0 <= 2*b*c*(a-h)-h^2*(k+b)+2*a*h*k+k*(-a^2+b^2)+b*(a^2+b^2) and   
   >        0 <= b   
   >   
   > and now abbreviate by r = 2*a*b*c+k*(b^2-a^2)+b*(a^2+b^2) to shorten   
   > it.   
   >   
   > And perhaps re-arrange according to 0 <= a resp 0 <= b.   
   >   
   > But may be you want something different.   
      
   Yes, I was hoping for something deeper than merely chopping and   
   abbreviating: different polynomials in a simplified overall structure.   
   But I suppose that Maple doesn't offer CAD, or that CAD is of no help   
   here.   
      
   Thanks for the suggestion,   
      
   Martin.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   

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