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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    clicliclic@freenet.de to All    |
|    Who is fastest?    |
|    27 Mar 16 15:22:21    |
      Hello!              How long does it take the popular integrators to evaluate the following       elementary indefinite integrals? Imagine them to appear in terms of some       series expansion:              INT(1/((1+x+2*x^2)^5*(3-2*x)^(11/2)),x)              INT(1/((1+x+2*x^2)^10*(3-2*x)^(21/2)),x)              INT(1/((1+x+2*x^2)^20*(3-2*x)^(41/2)),x)              and:              INT(1/((1+x+2*x^2)^5*(3-2*x+x^2)^(11/2)),x)              INT(1/((1+x+2*x^2)^10*(3-2*x+x^2)^(21/2)),x)              INT(1/((1+x+2*x^2)^20*(3-2*x+x^2)^(41/2)),x)              Does Maple beat FriCAS? Does Rubi beat Mathematica?              Martin.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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