Off topic a little:   
      
   First, I appreciate your effort to compile this   
   "Computer Algebra Independent Integration Tests".   
      
   However, I have a small advice for you:   
      
   Could you mark a test which returns non-elementary result   
   as "half-solved" if there exists elementary results?   
      
   Take this #319 as an example:   
      
   There are elementary results for this #319 test, Timofeev's   
   book page 194 has one elementary result.   
      
   Rubi's result used to contain F1 function, I consider such   
   result as not "fully solved", just "half-solved".   
      
   So I'd like to see there's a third state other than "passed"   
   and "failed", that'll reflect each system's strength more   
   accurately.   
      
   It should be simple: write a function to scan its argument   
   for non-elementary function, compare the difference   
   between optimal antiderivative and CAS's result.   
      
   FriCAS recently can solve this integral, the result is long,   
   elementary and correct.   
      
   You can verify (in MMA) by:   
      
   y=(2*3^(1/2)*Log[((3*x+3)*(3^(1/3))^2*((x^3+3*x^2+3*x+3)^(1/3))^2+((-9)*   
   x^2+(-18)*x+(-9))*(x^3+3*x^2+3*x+3)^(1/3)+(2*x^3+6*x^2+6*x)*3^(1/3))/(   
   x^3+3*x^2+3*x)]+((-1)*3^(1/2)*Log[((63*x^4+252*x^3+378*x^2+270*x+81)*(   
   (x^3+3*x^2+3*x+3)^(1/3))^2+(45*x^5+225*x^4+450*x^3+486*x^2+297*x+81)*3   
   ^(1/3)*(x^3+3*x^2+3*x+3)^(1/3)+(31*x^6+186*x^5+465*x^4+666*x^3+603*x^2   
   +324*x+81)*(3^(1/3))^2)/(x^6+6*x^5+15*x^4+18*x^3+9*x^2)]+(6*ArcTan[((63   
   *x^4+252*x^3+378*x^2+270*x+81)*((x^3+3*x^2+3*x+3)^(1/3))^2+(63*x^5+315*   
   x^4+630*x^3+648*x^2+351*x+81)*3^(1/3)*(x^3+3*x^2+3*x+3)^(1/3)+(38*x^6+228   
   *x^5+570*x^4+801*x^3+693*x^2+351*x+81)*(3^(1/3))^2)/((7*x^6+42*x^5+105*x^   
   4+135*x^3+90*x^2+27*x)*3^(1/2)*(3^(1/3))^2)]+6*ArcTan[((18*x^2+36*x+18)*3   
   ^(1/2)*(x^3+3*x^2+3*x+3)^(1/3)+(5*x^3+15*x^2+15*x+9)*3^(1/2)*3^(1/3))/((27   
   *x^3+81*x^2+81*x+27)*3^(1/3))])))/(18*3^(1/2)*3^(1/3))   
      
   Simplify[D[y,x]-1/((3*x + 3*x^2 + x^3)*(3 + 3*x + 3*x^2 + x^3)^(1/3))]   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)