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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 9,264 of 10,432    |
|    clicliclic@freenet.de to Albert Rich    |
|    Re: is your integrator output Davenport     |
|    05 Feb 17 10:58:29    |
      Albert Rich schrieb:       >       > On Tuesday, January 31, 2017 at 6:40:08 AM UTC-10, clicl...@freenet.de wrote:       > >       > > This can still be simplified considerably:       > >       > > 1/2*ATANH(x*(1 - x^2)/SQRT(1 - x^4))       > > + 1/2*ATAN(x*(1 + x^2)/SQRT(1 - x^4))       > >       >       > Nice! Is it possible to Riobooize the arctan term so the result is       > continuous at x^2=1?       >              As oldk1331 has pointed out, this is just a pointlike defect, which can       be automatically repaired by taking the usual limits x -> +-1.              Plain heresy: No general-purpose integrator needs to handle algebraic       integrands beyond Goursat pseudo-elliptics, and Goursat antiderivatives       do not exhibit discontinuities if done properly. This applies to both       square-root and cube-root integrands.              In general, Riobooizing a term c*ATAN(g(x)) of an antiderivative amounts       to rewriting g(x) as R(h(x)) where R is a rational function, and then       applying Rioboo's recursion to ATAN(R(h)). Here, c must be constant and       h(x) must remain finite in the x range of interest, else the entire       exercise would be pointless, or even disastrous.              Not seeing how the present ATAN argument x*(1 + x^2)/SQRT(1 - x^4) could       be expressed as some rational function R(h(x)), I am led to believe that       this ATAN term cannot be Riobooized.              Martin.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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