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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 9,265 of 10,432    |
|    antispam@math.uni.wroc.pl to clicliclic@freenet.de    |
|    Re: alarum: Risch integrator fails to di    |
|    07 Feb 17 04:09:45    |
      clicliclic@freenet.de wrote:       >       > clicliclic@freenet.de schrieb:       > >       > > antispam@math.uni.wroc.pl schrieb:       > > >       > > > My calculations indicate that points of order 3 correspond to       > > > u^2 = 1 +- 2*sqrt(3)/3. FriCAS says that integal is nonelementary,       > > > so something is wrong. Theory behind example is simple, so       > > > I believe it. I am not sure about points, but this is probably       > > > correct. So it remains to check FriCAS :(       > > >       > >       > > A simple theory should allow to read off simple antiderivatives for       > > the order-3 integrands.       > >       > > I suppose you have tried the integral on Axiom as well - the problem       > > would have to be quite old then.       > >       > > The points of order 3, 6 and 8 determined by me correspond to the       > > following three pairs of integrals:       > >       > > INT(x/((3*x^2 + 2*SQRT(2) - 3)*SQRT(x^3 - x)), x) = ?       > >       > > INT(x/((3*x^2 - 2*SQRT(2) - 3)*SQRT(x^3 - x)), x) = ?       > >       > > INT(x/((x^2 + 2*SQRT(2) + 3)*SQRT(x^3 - x)), x) = ?       > >       > > INT(x/((x^2 - 2*SQRT(2) + 3)*SQRT(x^3 - x)), x) = ?       > >       > > INT(x/((x^2 + 2*SQRT(10*SQRT(2) + 14) + 4*SQRT(2) + 5)*SQRT(x^3 - x)),       > > x) = ?       > >       > > INT(x/((x^2 - 2*SQRT(10*SQRT(2) + 14) + 4*SQRT(2) + 5)*SQRT(x^3 - x)),       > > x) = ?       > >       > > So your result for order 3 is confirmed. I derived these x^2 - u^2 from       > > a recursive definition of the division polynomials and then checked the       > > points [u,v] by iterating the group operation.       > >       > > I should mention that my statements about Goursat integrability       > > referred to Moebius mappings realizing the dihedral group D_2       > > (isomorphic to the Klein four-group K_4) only; the special nature of       > > the radicand x^3 - x may open other possibilities (thus, x <-> 1/x       > > swaps two roots and preserves the remaining two). Compare Goursat pp.       > > 113-118 for x^3 - 1.       > >       >       > Actually, Goursat considered the special radicand x^3 - x as well (on       > pp. 118-119) and concludes that no special pseudo-elliptic cases arise.       > I tend to believe him.              Hmm, you checked that for order 3 one gets special case, Goursat       says that there are none and you believe Goursat? I do not       understand.              > Meanwhile I can confirm that the order-3 integrals are elementary. The       > antiderivatives take less than 1000 Bytes to write down.       >       > Martin.              --        Waldek Hebisch              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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