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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 9,344 of 10,432    |
|    oldk1331@gmail.com to All    |
|    Re: fyi, new build of CAS integration te    |
|    11 Apr 17 03:17:31    |
      Martin:              Here's some comments (not excuses!) on the "failed 14 Timofeev problems":               (-2*cos(x)^3*(-1+sin(x))+cos(2*x)*sin(x))/(sin(x)^2*sqrt(-5+sin(x)^2))              This integrand is not real, because of the 'sqrt(-5+sin(x)^2)' part.        In FriCAS, 'complexIntegrate' can give a result. If replace       'sqrt(-5+sin(x)^2)' with 'sqrt(5-sin(x)^2)', then 'integrate' can       give a result.              (cos(1/2*x)+sin(1/2*x))/(%e^x)^(1/3)              If you simply rewrite it as (cos(1/2*x)+sin(1/2*x))/exp(x/3),       then FriCAS can solve it.              cos(1/3*x)^3/sqrt(%e^x)              Same as previous one, rewrite it as 'cos(1/3*x)^3/exp(x/2)'.              For other failures, 3 are errors, 8 are timeouts.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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